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-a^2-15a=0
We add all the numbers together, and all the variables
-1a^2-15a=0
a = -1; b = -15; c = 0;
Δ = b2-4ac
Δ = -152-4·(-1)·0
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{225}=15$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-15}{2*-1}=\frac{0}{-2} =0 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+15}{2*-1}=\frac{30}{-2} =-15 $
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